## sum of 5 times of an number and 3 times of another number is 63. sum of 7 times of the first number and 3 times of second number is 81. whic

Question

sum of 5 times of an number and 3 times of another number is 63. sum of 7 times of the first number and 3 times of second number is 81. which are the numbers ?​

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4 weeks 2021-08-18T22:55:52+00:00 2 Answers 0 views 0

1. GivEn:

• Sum of 5 times of a number and 3 times of another number is 63.
• Sum of 7 times of the first number and 3 times of second number is 81.

To find:

• Original numbers?

Solution:

☯ Let the first and second number be x and y respectively.

According to the Question:

• Sum of 5 times of a number and 3 times of another number is 63.

➯ 5x + 3y = 63 ⠀⠀⠀⠀⠀⠀⠀❬ eq (❶) ❭

• Sum of 7 times of the first number and 3 times of second number is 81.

➯ 7x + 3y = 81⠀⠀⠀⠀⠀⠀⠀ ❬ eq (❷) ❭

⠀━━━━━━━━━━━━━━━━━━━━━

Using Elimination method:

• Subtracting eq (1) from eq (2),

➯ (7x + 3y) – (5x + 3y) = 81 – 63

➯ 2x = 18

➯ x = 18/2

➯ x = 9

Now, Substituting value of “x” in eq (1),

➯ 5(9) + 3y = 63

➯ 45 + 3y = 63

➯ 3y = 63 – 45

➯ 3y = 18

➯ y = 18/3

➯ y = 6

Hence,

• The First number, x = 9
• The second number, y = 6