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sum of 5 times of an number and 3 times of another number is 63. sum of 7 times of the first number and 3 times of second number is 81. whic

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sum of 5 times of an number and 3 times of another number is 63. sum of 7 times of the first number and 3 times of second number is 81. whic

Question

sum of 5 times of an number and 3 times of another number is 63. sum of 7 times of the first number and 3 times of second number is 81. which are the numbers ?

## Answers ( )

GivEn:5times of a number and3times of another number is63.7times of the first number and3times of second number is81.To find:Solution:☯ Let the first and second number be

xandyrespectively.★

According to theQuestion:5times of a number and3times of another number is63.➯ 5x + 3y = 63 ⠀⠀⠀⠀⠀⠀⠀❬ eq (❶) ❭

➯ 7x + 3y = 81⠀⠀⠀⠀⠀⠀⠀ ❬ eq (❷) ❭

⠀━━━━━━━━━━━━━━━━━━━━━

Using Elimination method:➯ (7x + 3y) – (5x + 3y) = 81 – 63

➯ 2x = 18

➯ x = 18/2

➯ x =

9Now, Substituting value of “x” in eq (1),➯ 5(9) + 3y = 63

➯ 45 + 3y = 63

➯ 3y = 63 – 45

➯ 3y = 18

➯ y = 18/3

➯ y =

6Hence,

96Answer:x= 9 and y =6

Step-by-step explanation:let the first no be x and second be y

so according to question, 5x+3y=63 and 7x +3y=81 by solving the above equation you will get x=9 and y = 6