sum of 5 times of an number and 3 times of another number is 63. sum of 7 times of the first number and 3 times of second number is 81. whic

Question

sum of 5 times of an number and 3 times of another number is 63. sum of 7 times of the first number and 3 times of second number is 81. which are the numbers ?​

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Raelynn 4 weeks 2021-08-18T22:55:52+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-18T22:57:35+00:00

    GivEn:

    • Sum of 5 times of a number and 3 times of another number is 63.
    • Sum of 7 times of the first number and 3 times of second number is 81.

    To find:

    • Original numbers?

    Solution:

    ☯ Let the first and second number be x and y respectively.

    According to the Question:

    • Sum of 5 times of a number and 3 times of another number is 63.

    ➯ 5x + 3y = 63 ⠀⠀⠀⠀⠀⠀⠀❬ eq (❶) ❭

    • Sum of 7 times of the first number and 3 times of second number is 81.

    ➯ 7x + 3y = 81⠀⠀⠀⠀⠀⠀⠀ ❬ eq (❷) ❭

    ⠀━━━━━━━━━━━━━━━━━━━━━

    Using Elimination method:

    • Subtracting eq (1) from eq (2),

    ➯ (7x + 3y) – (5x + 3y) = 81 – 63

    ➯ 2x = 18

    ➯ x = 18/2

    ➯ x = 9

    Now, Substituting value of “x” in eq (1),

    ➯ 5(9) + 3y = 63

    ➯ 45 + 3y = 63

    ➯ 3y = 63 – 45

    ➯ 3y = 18

    ➯ y = 18/3

    ➯ y = 6

    Hence,

    • The First number, x = 9
    • The second number, y = 6
    0
    2021-08-18T22:57:42+00:00

    Answer:

    x= 9 and y =6

    Step-by-step explanation:

    let the first no be x and second be y

    so according to question, 5x+3y=63 and 7x +3y=81 by solving the above equation you will get x=9 and y = 6

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