## sum of 5 times of an number and 3 times of another number is63. sum of 7 times of the first number and 3 times of second number is 81. which

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## Answers ( )

Sumof5timesofanumberand3timesofanumberis63.Sumof7timesanumberand3timesofanumberis81.## _______________________

Findtheoriginalno.=??## ______________________

Letthefirstno.bexandsecondno.beySum of 5 times of a number and 3 times of a number is 63 .5x+3y=63––––(i)Sumof7timesofanumberand3timesofanumberis817x+3y=81–––––(ii)Subtractingeq(i)from(ii)7x+3y–5x–3y=81–632x=18x=9X=9puttingvalueofxineqi5x9+3y=6345+3y=633y=63–453y=18y=6Y=6## _______________

Firstno=9Secondno=6Answer:first number = 9 and second number = 6

Step-by-step explanation:let the first number be x and the second number be y.

then by the given conditions we get

5x + 3y = 63 ( first equation )

7x + 3y = 81 ( second equation)

subtracting the second equation with the first equation we get:

2x = 18

x = 18/2 = 9

x = 9

substitute x = 9 in first equation :

(5 × 9) + 3y = 63

45 + 3y = 63

3y = 63 – 45 = 18

3y = 18

y = 18/3 = 6

y= 6

therefore the first number(x) = 9

the second number(y) = 6