sum of three consecutive of 8 in 888 find the multiples ​

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sum of three consecutive of 8 in 888 find the multiples

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Adalyn 7 months 2021-10-15T21:02:11+00:00 1 Answer 0 views 0

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    2021-10-15T21:03:23+00:00

    Let the multiples are x, (x+1) and (x+2).

    The sum of three consecutive multiples of 8 = 888

    According to condition,

    8x+8(x+1)+8(x+2) = 888

    or, 8x+8x+8+8x+16 = 888

    or, 24x+24 = 888

    or, 24x = 888-24

    or, 24x = 864

    or, x = 864/24

    or, x = 36

    So, x = 36,

    (x+1) = (36+1) = 37,

    and (x+2) = (36+2) = 38.

    Hence, the multiples are 36, 37 and 38 respectively.

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