Suppose the half- life of a certain radioactive substance is 12 days and there are 18 grams present initially. Find the time when there will

Question

Suppose the half- life of a certain radioactive substance is 12 days and there are 18 grams present initially. Find the time when there will be 20% of the initial substance remaining.

in progress 0
Adeline 4 weeks 2021-08-21T23:25:27+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-21T23:26:33+00:00

    Answer:

    4.8 days i hope it will help you

    Step-by-step explanation:

    18 g is active for 24 days

    then for 1 g it will active for 24/18

    and for 20 %

    20% of 18 g = 3.6

    the time is equal to 24*3.6/18

    that is equal to 4.8 days

    0
    2021-08-21T23:27:05+00:00

    Answer:

    t ≈ 27.86 days

    Step-by-step explanation:

    a^{b}=clog_{a}c = b

    ~~~~~~~

    t27.86 days

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )