tan (A+B) = √3 and tan (A-B) =1 find the value of A and B..​

Question

tan (A+B) = √3 and tan (A-B) =1
find the value of
A and B..​

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Clara 1 week 2021-09-10T20:42:53+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-10T20:44:24+00:00

    tan(A+B) = √3 and tan60°=√3

    =(A+B) = 60° -(i)

    &

    tan(A-B) =1/√3 and tan30°=1/√3

    =(A-B) =1/√3 -(ii)

    (i) +(ii)

    A+B=60°+ (A-B=30°) [ab +B, -B se cut jaega]

    = 2A=90°

    =A=90°/2

    =A=45°

    putting value of A in (i)

    A+B=60°

    45°+B =60°

    B= 60°-45°

    B=15°

    hope it will help u. plzz mark me brainlist and follow me

    0
    2021-09-10T20:44:34+00:00

    Answer:

    So easy question… Wait I will explain you

    Step-by-step explanation:

    • Given-tan(A+B)=3 and tan(A-B)=1
    • (A+B)=3 1eq.
    • (A-B)=1 2 eq.
    • on eliminating 1 and 2 eq
    • A+B=3
    • A-B=1
    • = A=31
    • putting the value of A in 1eq.
    • 31 +B=3
    • B=33 +1
    • B=1
    • So the value of A=31 And B=1
    • Thank you hope it will be helpful to you.

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