the 11th term from the end of the Ap 10,7,4-…-62 is​

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the 11th term from the end of the Ap 10,7,4…….-62 is​

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Sarah 3 days 2021-09-14T05:50:44+00:00 1 Answer 0 views 0

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    2021-09-14T05:51:54+00:00

    Step-by-step explanation:

    The sequence given is 10, 7, 4, ….-62.

    First we need to find out number of terms in this sequence.

    ‘a’ = 10, ‘d’ = -3, last term = -62

    tn =a+(n−1)d

    ⟹ −62=10+(n−1)(−3)

    ⟹ −62=13−3n

    ⟹ 3n=75 or n=25.

    The number of terms in the sequence is 25.

    The 11th term from the end is same as the 15th term from the first.

    So, 

    t15=10+(15−1)(−3)

    ⟹t15=10+(14)(−3)

    ⟹t15=−32.

    The 11th term from the end is -32.

    hope its helpful for you mate.....

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