the 5th term of an aritamatic sequence 38and the 9th term is 66 what is its first term and the 15th term​

Question

the 5th term of an aritamatic sequence 38and the 9th term is 66 what is its first term and the 15th term​

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Evelyn 4 weeks 2021-10-01T15:12:07+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-01T15:13:40+00:00

    Answer:

    HOPE IT HELPS YOU

    Step-by-step explanation:

    5th term= a+4d

    Or 38=a+4d -equation 1

    9th term=a+8d

    Or 66=a+8d -equation 2

    Eq.1-eq2

    Or a+4d=38

    a+8d=66

    – – –

    Or -4d= -28

    Or d=28/4

    d=7

    Putting value of d in equation 1

    a+4d=38

    Or a+28=38

    Or a=38-28

    Or a=10

    Now 25th term

    25th term = a+24d

    Or 10+24*7

    Or 25th term=10+168

    Or 25th term=178

    0
    2021-10-01T15:13:58+00:00

    The first term is 10 and the 15th term is 138

    Step-by-step explanation:

    5th term-38

    9th term-66

    15th term =?

    An=a+(n-1)xd

    38=a+(5-1)xd

    38=a+4d —–(1)

    An=a+(n-1)xd

    66=a+(9-1)xd

    66=a+8d—–(2)

    solving both the equations:-

    a+4d=38

    a+8d=66

    – – –

    -4d=-28

    4d=28

    d = 28/4

    d=7

    put d in (1) to find a

    a = 10

    put a =10 and d= 7 in

    An=a+(n-1)d

    you will get the answer as 1st term =10

    15th term = 138

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