The angle of a triangle are given below, find them. 2xt10 x-5 4x+20

Question

The angle of a triangle are given below, find them. 2xt10 x-5 4x+20

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Bella 1 month 2021-09-16T14:41:22+00:00 2 Answers 0 views 0

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    0
    2021-09-16T14:42:46+00:00

    Answer:

    We know that sum of all angles of a triangle is equal to 180°

    So, (x+10)° + (2x-30)° + (x) ° = 180°

    => (x+2x+x)° + (10-30)° = 180°

    => (4x)° – 20° = 180°

    => 4x = 200

    => x=50 Ans

    (Please mark me as brainlist answer)

    0
    2021-09-16T14:43:16+00:00

    Answer:

    Angle= (2x-10),(x-5),(4x+20)

    According to angle sum property in a Δ,

    => 2x-10+x-5+4x+20=180°

    => 7x + 5=180°

    => 7x = 180 – 5

    => 7x = 175

    => x = 175/7 = 25

    Angle A= 2x – 10= 2×25-10= 40°.

    Angle B= x -5= 25-5 = 20°.

    Angle C= 4x + 20= 4×25+20= 120°.

    Step-by-step explanation:

    HOPE IT HELPS

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