## The area of a rectangular plot is 528 m². The length of the plot (in metres) is one mo than twice its breadth. We need to find the leng

Question

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## Answers ( )

Answer:Solution :

Let the Breadth be b

Then, length will be 2b + 1

It is given that Area of reactangular plot is 528 m².

According to question now :

Area = Length × Breadth

528 = (b) (2b + 1)

528 = 2b² + b

2b² + b – 528 = 0

Now, by using splitting term we get,

2b² – 32b + 33b – 528 = 0

2b (b – 16) + 33 (b – 16) = 0

(2b + 33) (b – 16) = 0

If x – 16 = 0, then x = 16

If 2b + 33 = 0, then b = -33/2

Therefore, Breadth = 16 meter.

So,

Length = 2b + 1 = 2(16) + 1 = 32 + 1 = 33 m

Hence,

Length of the reactangular plot = 33 m

Breadth of the reactangular plot = 16 m

Answer:Area =528m^2

Let Breadth be b

Then length l = 2b+1

So (b)(2b+1)=528

⇒2b^2+b − 528=0

⇒2b^2 − 32b + 33b − 528 = 0

⇒2b(b−16) + 33(b−16) = 0

⇒(2b+33)(b−16)=0

So

b=16ml=33m