The area of rectangle is x2 -23 +132. If its breadth is (x-12), find its length.​

Question

The area of rectangle is x2 -23 +132. If its breadth is (x-12), find its length.​

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Gianna 1 month 2021-10-27T01:41:27+00:00 2 Answers 0 views 0

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    2021-10-27T01:42:53+00:00

    \large{\boxed{\red{\sf{A=l×b}}}}

    {\sf{x²-23x+132=l×(x-12)}}

    {\sf{l=(x²-23x+132)÷(x-12)}}

    {\sf{l=(x²-11x-12x+132)÷(x-12)}}

    {\sf{l=(x(x-11)-12(x-11))÷(x-12)}}

    {\sf{l=((x-11)(x-12))÷(x-12)}}

    {\red{\sf{l=(x-11)}}}

    0
    2021-10-27T01:42:53+00:00

    Answer:

    ABCD is rectangle. Its diagonals meet at O. OA = 2x ‑ 1 and OD = 3x ‑ 2. Find x ABCD is rectangle. Its diagonals meet at O. OA = 2x ‑ 1 and OD = 3x ‑ 2. Find x 1 2 3 ‑1

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