. The area of the trapezium is 912 cm square .The length of its parallel sides are in the ratio 6:13 and the height is 24 cm .Find the lengt

Question

. The area of the trapezium is 912 cm square .The length of its parallel sides are in the ratio 6:13 and the height is 24 cm .Find the lengths of the parallel sides.

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Cora 1 month 2021-10-27T03:20:17+00:00 2 Answers 0 views 0

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    0
    2021-10-27T03:21:32+00:00

    Solution :

    Let the ratio of parallel sides of trapezium be a part of x

    Then the sides will be

    • 6x

    • 13x

    Now , as we know that

    Area of trapezium = ½ × (sum of parallel sides) × Height

    912 = 1/2 × (6x + 13x) × 24

    ➩ 912 × 2 = 19x × 24

    ➩ 1824 ÷ 24 = 19 x

    ➩ 76 = 19x

    ➩ 76 ÷ 19 = x

    ➩ x = 4

    _________________________

    Now , finding the parallel sides

    ➨ 6x

    ➨ 6(4)

    ➨ 24 cm

    _______________

    ➥ 13x

    ➥ 13(4)

    ➥ 52 cm

    _________________________

    Hence , length two parallel sides = 24 cm & 52 cm .

    0
    2021-10-27T03:21:35+00:00

    Answer:

    DATA GIVEN:

    AREA OF TRAPEZIUM = 912 CM SQUARE.

    LENGTH IF THE PARALLEL SIDES ARE IN THE RATIO 6:13.

    HEIGHT =24 CM.

    TO FIND:

    LENGTHS OF THE PARALLEL SIDES.

    FORMULA USED:

    (sum \: of \: parallel \: sides) \times h \times  \frac{1}{2}  =  \frac{sum \: of \: parallel \: sides \:  \times h}{2}

    SOLUTION:

    LET THE PARALLEL SIDES BE 6X AND 13 X.

    AREA OF TRAPEZIUM = SUM OF PARALLEL SIDES×H/2

    =>912 =(6X+13X)×24/2

    =>912×2=19X×24

    =>1824=456X

    =>X=1824/456=4

    WE GOT X=6

    NOW 6X=6×4=24 CM

    13X=13×4=52 CM

    HENCE LENGTH OF PARALLEL SIDES ARE 24 CM AND 52 CM.

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