The area of triangle with given two sides 18cm and 10cm respectively and perimeter equal to 42 cm is:​

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The area of triangle with given two sides 18cm and 10cm respectively and perimeter equal to 42 cm is:​

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Serenity 2 months 2021-10-09T18:07:56+00:00 2 Answers 0 views 0

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    0
    2021-10-09T18:09:10+00:00

    Given:

    Perimeter of triangle is 42 cm.

    Measure of two sides of triangle are 18 and 10 cm respectively.

    To Find:

    What is the area of triangle?

    Solution: Let the third side of triangle be x cm. Therefore,

    ➯ Sum of all sides = Perimeter

    ➯ 18 + 10 + x = 42

    ➯ x = 42 – 28

    ➯ x = 14 cm { Third sides of triangle }

    Now, For finding area of ∆ we will use Heron’s Formula.

    First find the Semi-Perimeter (s)

    ➬ s = (Sum of all sides / 2)

    ➬ s = (42/2)

    ➬ s = 21

    ★ Formula = √s(s–a) (s–b) (s–c) ★

    ➛ √21 (21 – 18) (21 – 10) (21 – 14)

    ➛ √21 (3) (11) (7)

    ➛ √3 7 3 11 7

    ➛ 3 7 √11

    ➛ 21√11 cm²

    Mark as BRAINLIEST

    0
    2021-10-09T18:09:43+00:00

    Given,

    Side a=18cm

    Side b=10cm

    Perimeter=42cm=a+b+c

    :. Putting value

    42=18+10+c

    42=28+c

    42-28=c

    14=c

    Now,

    S=(a+b+c)/2

    :. Putting value

    S=42/2

    S=21

    Now according to Heron’s formula-

    Area of a triangle

    =√{s(s-a)(s-b)(s-c)}

    :. Putting value

    =√{21(21-18)(21-10)(21-14)}

    =√{21(3)(11)(7)}

    =√4851

    =21√11cm²

    (ÆÑẞWĒRẞ)

    #Mãrk åß thē Brāìñlïêßt

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