The base of an isosceles triangle is 12 cm and its perimeter is 32 cm. find the area.​

Question

The base of an isosceles triangle is 12 cm and its perimeter is 32 cm. find the area.​

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Madeline 1 month 2021-08-14T02:05:48+00:00 2 Answers 0 views 0

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    0
    2021-08-14T02:07:40+00:00

    isoscelestriangle:

    Base=12cm

    sum of other 2 Sides=32-12=20

    equal sides=20/2=10cm each

    sides of this triangle 12, 10, 10

    semiperimeter=(12+10+10)/2 = 32/2=l6

    Area =vs (s-a)(s-b)(s-c)

    =v16 (16-12) (16-10) (16-10)

    =v16x4x6x6=48cm2

    0
    2021-08-14T02:07:41+00:00

    Answer:

    Let x be the equal side.

    ==>Perimeter:2x+12=32.

    x=10cm.

    Height of the base=8 (by solving using Pythagorean theorem).

    Area of triangle=1/2*b*h.

    Area of triangle =1/2*12*8.

    Area of triangle=48cm^2.

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