The cast of 2 aronges and I apples i 0 146 and the cast of 3 orange and I apples is B 74. 1er us find the cast of a

Question

The cast of 2 aronges and I apples i
0 146 and the
cast of 3 orange and I apples
is B 74.
1er us find the
cast of an orange
and and apple​

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Ariana 1 month 2021-08-17T20:53:28+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-17T20:54:36+00:00

     \huge \bold { \underline{Correct \:  Question?}}

    The cost of 2 oranges and 3 apples is 46 and the cost of 3 oranges and 5 apples is 74.

    Find the cost of an orange and an apple.

     \huge \bold { \underline{Solution}}

    Given:-

    • The cost of 2 oranges and 3 apples is 46.
    • The cost of 3 oranges and 5 apples is 74.

    To prove:-

    • Cost of an orange and an apple.

    Solution:-

    ➣Let the cost of oranges be x.

    ➣Let the cost of apples be y.

    According To Question:-

    ➣2x  + 3y = 46

    ➣3x + 5y = 74

    Now multiply equation (i) by 3 and equation (ii) by 2.

    ➣6x + 9y = 138

    ➣6x + 10y = 148

    _________________________________

    ➣ - 1y =  - 10

    y = 10

    In substituting in (I) for X we will get X=

    ➣2x  + 3y = 46

    ➣2x + 30 = 46

    ➣2x = 46 - 30

    2x = 16

    x = 18

    So the cost of:-

    • Orange:- 18
    • Apple:- 10.

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18:9+8+9*3-7:3-1*13 = ? ( )