The common factor of 20, 28 and 36 is 2(occuring twice). T 28 and 36 is 2 x 2 = 4 EXERCISE 3.6 18,48 1. Find the HCF of

Question

The common factor of 20, 28 and 36 is 2(occuring twice). T
28 and 36 is 2 x 2 = 4
EXERCISE 3.6
18,48
1. Find the HCF of the following numbers:
(b) 30.42
( 18.60
(e) 36,84
34. 102
Lot 70, 105, 175
by 91, 112, 49 (1) 18.54.81
(1) 12,45,75
2. What is the HCF of two consecutive
(a) numbers?-) (b) even numbers?-2 (c) odd numbers?​

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Eva 1 month 2021-10-27T01:44:51+00:00 1 Answer 0 views 0

Answers ( )

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    2021-10-27T01:46:13+00:00

    Step-by-step explanation:

    1. common factor of 20

    Answer = 2,4,5,10,20

    1. 28×2=56
    2. 36×= 72
    3. 56+72= 812
    4. Answer =812
    1. ex=3.6
    2. 30.42 =2,3,5,6, 10,30,=42=2,6,14,42
    3. 18.60=2,3,8,18,=60=2,6,10,12,15,20,30,60
    4. Answer HCF=42,60

    1. 36,48
    2. 36=2,4,6,9,12,18,36
    3. 48=2,6,12,28,48
    4. 34=2,17,34,
    5. 102=2,17,34,102

    Answer=HCF=36,48,34,102

    Lot=70= 2,7,10,14,35,70

    105=15,21,35,105

    175=25,35,175

    answer=HCF= 70,105,175

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