## The diameter of a road roller 120cm long is 84cm. If it takes 500 complete revolutions to level the playground, determine the cost of l

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## Answers ( )

2r = 84cm

∴ r = 84/2cm = 42cm h

= 120cm

Area of the playground leveled in one complete

revolution = 2πrh = 2 × 22/7 × 42 × 120 × 31680cm²

∴ Area of the playground = 31680 × 500cm²= (31680 x 500)/(100 x 100)m² = 1584m²

cost of leveling=Rs475.20

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