The diameter of a road roller 120cm long is 84cm. If it takes 500 complete revolutions to level the playground, determine the cost of l

Question

The diameter of a road roller 120cm long is 84cm. If it takes 500 complete revolutions to level the playground, determine the cost of
leveling it at the rate of 30 paise per sq metre.​

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Remi 2 weeks 2021-09-09T16:12:34+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-09T16:14:03+00:00

    answer

    2r = 84cm

    ∴ r = 84/2cm = 42cm h

    = 120cm

    Area of the playground leveled in one complete

    revolution = 2πrh = 2 × 22/7 × 42 × 120 × 31680cm²

    ∴ Area of the playground = 31680 × 500cm²= (31680 x 500)/(100 x 100)m² = 1584m²

    cost of leveling=Rs475.20

    0
    2021-09-09T16:14:13+00:00

    Step-by-step explanation:

    Hope this answer helps you

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