the digits of a two digit number differ by 3 . If digits are interchanged and the resulting number is added to the original number .we get 1

Question

the digits of a two digit number differ by 3 . If digits are interchanged and the resulting number is added to the original number .we get 121 . Find the original number???

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Luna 1 month 2021-08-12T13:06:47+00:00 2 Answers 0 views 0

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    0
    2021-08-12T13:08:12+00:00

    Answer:

    It is given that the sum is 121. The units digit is 4 and therefore the tens digit is 4 + 3 = 7. Hence, the number is 74 or 47

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    2021-08-12T13:08:35+00:00

    Answer:

    Let us take the two digit number such that the digit in the units place is x. The digit

    in the tens place differs from x by 3. Let us take it as x + 3. So the two-digit number is

    10 (x + 3) + x = 10x + 30 + x = 11x + 30.

    With interchange of digits, the resulting two-digit number will be 10x + (x + 3) = 11x + 3

    If we add these two two-digit numbers, their sum is

    (11x + 30) + (11x + 3) = 11x + 11x + 30 + 3 = 22x + 33

    It is given that the sum is 121.

    Therefore, 22x + 33 = 121

    22x = 121 – 33

    22x = 88

    x=4

    The units digit is 4 and therefore the tens digit is 4 + 3 = 7.

    Hence, the number is 74 or 47.

    Step-by-step explanation:

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