The distance of the straight line from the origin is 6 and angle made by the normal from the origin to the line with the positive direction

Question

The distance of the straight line from the origin is 6 and angle made by the normal from the origin to the line with the positive direction of x-axis is 150 degrees , then the equation of the straight line is
a) \sqrt{3}-y+12=0
b) x-\sqrt{3}y+12=0
c) \sqrt{3}y-x+12=0
d) \sqrt{3}x-y-12=0

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Ruby 1 month 2021-09-22T00:56:47+00:00 1 Answer 0 views 0

Answers ( )

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    2021-09-22T00:58:37+00:00

    Step-by-step explanation:

    The distance of the straight line from the origin is 6 and angle made by the normal from the origin to the line with the positive direction of x-axis is 150 degrees , then the equation of the straight line is

    a) \sqrt{3}-y+12=0

    b) x-\sqrt{3}y+12=0

    c) \sqrt{3}y-x+12=0

    d) \sqrt{3}x-y-12=0

    i think option 1 is the correct answer….

    hey mark it as the brainliest

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