the first and last term of an A..p are 1 and 11 respectively if the sum of its term is 36 the number term is (1) 8 (2) 7 (3) 4 (4) 6​

Question

the first and last term of an A..p are 1 and 11 respectively if the sum of its term is 36 the number term is (1) 8 (2) 7 (3) 4 (4) 6​

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Luna 4 months 2022-01-06T16:53:29+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-01-06T16:54:57+00:00

    Answer:

    Sum of terms of AP= (no of terms/2) (1st terms + last terms)

    so, 36= n/2 × ( 1+11) [ n= no of terms]

    n= 6

    0
    2022-01-06T16:55:02+00:00

    Answer:

    6

    Step-by-step explanation:

    Using

    sum =  \frac{n}{2} (first \: term +  \: last \: term)

    we get

    36 =  \frac{n}{2} (1 + 11)

    72 = n(12)

    n = 6

    Therefore there are 6 terms

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