The length of a rectangle exceeds twice it’s breadth by 2 cm if the perimeter is 28 cm.Find length and breadth. By Substitution Method​

Question

The length of a rectangle exceeds twice it’s breadth by 2 cm if the perimeter is 28 cm.Find length and breadth. By Substitution Method​

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Evelyn 3 weeks 2021-08-19T21:20:01+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-19T21:21:07+00:00

    Answer:

    Let the breadth be x.

    And length be x+2

    2(x+2+x)=28

    2(2x+2)=28

    4x+4=28

    4x. =28-4

    4x. =24

    x=24/4=6 ans

    Breadth=6 cm

    length=6+2= 8 cm ans.

    0
    2021-08-19T21:21:15+00:00

    _________________________

    Gɪᴠᴇɴ :

    • The length of rectangle exceeds twice its breadth by 2 cm
    • Perimeter of rectangle = 28 cm

    _________________________

    T Fɪɴᴅ :

    • Length = ?
    • Breadth = ?

    _________________________

    Sᴏʟᴜᴛɪᴏɴ :

    Let the breadth be x , then the length will be 2x + 2 .

    As we know that

    Perimeter of rectangle = 2( l + b )

    ➮ 2(2x + 2 + x)

    ➮ 2(3x + 2)

    ➮ 6x + 4 = 28

    ➮ 6x = 24

    ➮ x = 4

    Now , finding length & breadth

    Breadth = x = 4cm

    Length = 2x + 2 = 10cm

    ________________________

    Hence , length = 4 cm & breadth = 10 cm .

    ________________________

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