the lenth of a rectangle is 10 m more than its breath if the perimeter of the rectangle is 80 m find the dimension of the rectangle​

Question

the lenth of a rectangle is 10 m more than its breath if the perimeter of the rectangle is 80 m find the dimension of the rectangle​

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Allison 1 week 2021-09-14T18:27:41+00:00 1 Answer 0 views 0

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    2021-09-14T18:29:08+00:00

    Step-by-step explanation:

    The perimeter of an object is the sum of all it’s lengths. So in this problem, 80m = side1 + side2 + side3 + side4.

    Now a rectangle has 2 sets of equal length sides.

    So 80m = 2xSide1 + 2xSide2

    And we are told that the length is 10m more than it’s breadth.

    So 80m = 2xSide1+(10+10) + 2xSide2

    So 80m = 2xS1+20 +2S2

    80 = 2x + 2y + 20

    If it were a square, x + y would be the same

    so

    60 = 4x side1

    so side 1 = 60/4 = 15m

    So side 1 = 15m, side 2 = 15m, side 3 = 15m+10m side 4 = 15+10m

    So s1 = 15m, s2 = 15m, s3 = 25m, s4 = 25m.

    Perimiter = 80m and the length of th e rectangle is 10m longer than the breadth

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