## The mean and standard deviation of a population are 11,795 and 14054 respectively. If n=50 ,find 95% confidence interval for the mean.

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## Answers ( )

Answer:Step-by-step explanation:Here mean of population , mu = 11795S.D of population , sigma= 1405x bar = 11795

n = sample size = 50 , maximum error = Z alpha by 2 x sigma by root n

Z alpha by 2 for 95% confidence = 1.96

Max. error, E = Z alpha by 2 x sigma/ root n = 1.96 x 14054/ root of(50) = 3899

Therefore, Confidence interval = ( x bar – z alpha by 2 . sigma / root n , x bar + Z alpha by 2 . sigma / root n

=(11795 – 3899, 11795 + 3899)

=(7896, 15694)