The mean and standard deviation of a population are 11,795 and 14054 respectively. If n=50 ,find 95% confidence interval for the mean.

Question

The mean and standard deviation of a population are 11,795 and 14054 respectively. If n=50 ,find 95% confidence
interval for the mean.

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Delilah 1 month 2021-08-12T17:56:54+00:00 1 Answer 0 views 0

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    2021-08-12T17:58:29+00:00

    Answer:

    Step-by-step explanation:

    Here mean of population , mu = 11795

    S.D of population , sigma = 1405

    x bar = 11795

    n = sample size = 50 , maximum error = Z alpha by 2 x sigma by root n

    Z alpha by 2 for 95%  confidence = 1.96

    Max. error, E = Z alpha by 2 x sigma/ root n = 1.96 x 14054/ root of(50) = 3899

    Therefore, ┬áConfidence interval = ( x bar – z alpha by 2 . sigma / root n , x bar + Z alpha by 2 . sigma / root n

    =(11795 – 3899, 11795 + 3899)

    =(7896, 15694)

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