The perimeter of a triangle is 15x^2-23x+9 and two of its sides are 5x^2+8x-1 and6x^2- 9x+4. Find the third side.​

Question

The perimeter of a triangle is 15x^2-23x+9 and two of its sides are 5x^2+8x-1 and6x^2-
9x+4. Find the third side.​

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Camila 2 days 2021-11-25T21:07:44+00:00 1 Answer 0 views 0

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    2021-11-25T21:09:02+00:00

    Step-by-step explanation:

    Formula For Perimeter of triangle = (side) 1+(side) 2

    +(side) 3

    Using formula We have :-

    (15x^2 −23x+9) = 5x^2+8x−1+6x ^2 −9x+4+(side) 3

    ⇒ (15x^2 −23x+9)= 11x^2−x+3+(side) 3

    ⇒ (side) 3 =15x^2−23x+9−11x^2+x−3

    ⇒ (side) 3 = 4x^2−22x+6

    The answer is 4x^2 −22x+6

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