The perimeter of the rectangular garden is 180 meters.If the length of the garden is 10 meters more than is width ,What wil be the area of t

Question

The perimeter of the rectangular garden is 180 meters.If the length of the garden is 10 meters more than is width ,What wil be the area of the garden

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Everleigh 1 week 2021-09-10T20:24:59+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-10T20:26:20+00:00

    Answer:

    \bigstar{\bold{Area\:=\:2000\:m^{2} }}

    Step-by-step explanation:

    \Large{\underline{\underline{\bf{Given:}}}}

    • Perimeter of rectangular garden = 180 m
    • Length of garden is 10 m more than width

    \Large{\underline{\underline{\bf{To\:Find:}}}}

    • Area of the garden

    \Large{\underline{\underline{\bf{Solution:}}}}

    → Let length be l and breadth be b

    → By given data

      l = b + 10

    Peimeter of a rectangle = 2( l + b )

      which is give as 180 m

    → Substituting the value of l we get

      2 ( b+ 10 +b ) = 180

     4b + 20 = 180

      4b = 160

        b = 40 m

    → l = b+ 10 = 40 + 10 = 50 m

    Area of rectangle = l × b

      Area = 40 × 50 = 2000 m²

    \boxed{\bold{Area\:=\:2000\:m^{2} }}

    \Large{\underline{\underline{\bf{Notes:}}}}

    → Perimeter of a rectangle = 2(l + b)

    → Area of a rectangle = l × b

    where l is the length and b is the breadth of the rectangle

    0
    2021-09-10T20:26:26+00:00

    \huge\underline\bold{QUESTION:-}

    _________________________________________

    The perimeter of the rectangular garden is 180 meters. If the length of the garden is 10 meters more than the width What will be the area of the garden

    __________________________________________

    \huge\underline\bold{TO FIND:-}

    __________________________________________

    The area of the rectangle if the length exceeds the breadth by 10 and the perimeter is 180 meters

    __________________________________________

    \huge\underline\bold{SOLUTION:-}

    \rightarrow Perimeter of the rectangle= 180ms

    \rightarrow Let the breadth of rectangle= x ms

    \rightarrow Length of the rectangle= x+10 ms

    Perimeter= Sum of all these sides

    180 ms= 2(x+x+10)

    180 ms= 4x+20

    4x= 160 ms

    x=40 ms

    ★ Breadth of the rectangle = 40 ms

    ★ Length of rectangle= x+10 = 40+10=50 ms

    \huge\underline\bold{ANSWER:-}

    _________________________________

    ★ Area = Length × breadth

    ★ Area = 40×50 ms²

    ★ Area =2000ms²

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