The point on the curve y equal to 12x-x square where the slope of the tangent is 0 will be ?

Question

The point on the curve y equal to 12x-x square where the slope of the tangent is 0 will be ?

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Charlie 5 months 2021-12-29T16:35:42+00:00 2 Answers 0 views 0

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    0
    2021-12-29T16:36:44+00:00

    Step-by-step explanation:

    Let the point be P(x,y)

    y=12x−x^2

    (dy/dx) = 12−2(x1)

    (x1,y1)

    since slope of tangent is zero

    so ( dy/dx) =0

    (x1,y1)

    12−2(x1) =0

    2(x1) =12

    (x1) = 6

    Also curve passing through tangent

    (y1) =12(x1) – (x1)^2

    (y1) =12×6−36

    (y1) =72−36

    (y1) =36

    So, The points are (6,36).

    Hope this will help you

    please try to mark it as brainliest…..

    0
    2021-12-29T16:37:03+00:00

    Answer:

    0

    Step-by-step explanation:

    MARK ME AS BRAINLIST……..

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