The probability that a candidate can pass in an exam is 0.6i)What is the probability that he pass in the third trial?ii)What is the probabil
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Answers ( )
14
45
Explanation:
P(A or B) = P(A) + P(B) – P(A and B)
Take
A = Mr x passes Mathematics
B = Mr x passes Statistics
Then we have
P(A or B) = 4/5 = 2/3 + 4/9 – P(A and B)
⇒
P(A and B) = 2/3 + 4/9 – 4/5
=
30
+
20
−
36
45
=
14
45