The radius of a hemispherical balloon increases from 6 cm to 12 cm as air is being pumped into it. The ratio of the surface areas of t

Question

The radius of a hemispherical balloon increases from 6 cm to 12 cm as air is being pumped into it. The ratio of the surface areas of the balloon in the two cases is ___ *

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Savannah 1 month 2021-08-12T04:57:31+00:00 2 Answers 0 views 0

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    0
    2021-08-12T04:58:39+00:00

    We know,

     \small \textbf{Surface Area of Hemisphere} =  \tt \blue{3 \pi{r}^{2} } \\

    Now,

    • Ratio of Surface Areas of balloons in two cases —

     =  >  \frac{ \tt { \cancel{3 \pi}{r}^{2} }}{ \tt { \cancel{3 \pi}{R}^{2} }}  \\  \\   =  > \frac{ {r}^{2} }{ {R}^{2} }  =   \frac{ {(6)}^{2} }{ {(12)}^{2} }  \\  \\  =  >  \frac{36}{144}  \:  \:  =  \frac{1}{4}  \\  \\  \huge =  >  \pink{1 : 4}

    0
    2021-08-12T04:58:43+00:00

    Answer:

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