the roots of the quadratic equation are x²+3x-(k+1)(k+6)=0​

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the roots of the quadratic equation are x²+3x-(k+1)(k+6)=0​

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Abigail 2 months 2021-10-04T21:08:39+00:00 1 Answer 0 views 0

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    2021-10-04T21:09:39+00:00

    Answer:

    -3+_sqroot(9-4(k+1)(k+12)/2

    Step-by-step explanation:

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