The smallest number which when devided by 24,36 and 64 leaves 4 as remainder in each case.

Question

The smallest number which when devided by 24,36 and 64 leaves 4 as remainder in each case.

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Caroline 3 weeks 2021-10-01T13:57:43+00:00 2 Answers 0 views 0

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    0
    2021-10-01T13:58:49+00:00

    Answer:

    Step-by-step explanation:

    Let’s call the number x

    Therefore when x is divided by 24 36 64 leaves reminder as 4

    So x is a factor of 20 32 60

    So we will find the HCF of 20,32,60

    And that is 4

    Hence the answer is 4

    0
    2021-10-01T13:59:03+00:00

    The smallest number divisible by all 24, 36, 54 is:

    LCM(24, 36, 54) = 216

    Thus, to get 5 as remainder, we need to add 5 to 216 (as 216 is the smallest number which gives remainder 0 when divided by 24 or 36 or 54)

    216 + 5 = 221

    For 12, 221 gives 18 as quotient and 5 as remainder

    For 36, 221 gives 6 as quotient and 5 as remainder

    For 54, 221 gives 4 as quotient and 5 as remainder

    Hence, 221 is required number

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