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The sum of first 6 terms of an arithmetic Sequence is 99 and the 6th team is 39. (a find the sum of x3 and x4 b write the 3rd

Home/Math/The sum of first 6 terms of an arithmetic Sequence is 99 and the 6th team is 39. (a find the sum of x3 and x4 b write the 3rd

The sum of first 6 terms of an arithmetic Sequence is 99 and the 6th team is 39. (a find the sum of x3 and x4 b write the 3rd

Question

The sum of first 6 terms of an arithmetic Sequence is 99 and the 6th team is 39. (a find the sum of x3 and x4 b write the 3rd team @ write the sequence.

## Answers ( )

Step-by-step explanation:The sum of the first N terms of the arithmetic sequence

is

N*(A1 + An)/2 = SUM

6*(A1 + A6)/2 = 99

6*(A1 + 39)/2 = 99

3(a1+39) = 99

a1 + 39 = 33

a1 = -6

Next for divided difference D, An = a1 + (n-1)*D

39 = -6 + (6-1)*D

39 = -6 + 5*D

45 = 5D

D = 9

The sequence is -6, 3, 12, 21, 30, 39

12+21 = 33

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