## The sum of the age of a man and his son is 45 years.five years ago,the product of their age was four times the man’s age at that time.find t

Question

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## Answers ( )

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Step-by-step explanation:Ans : 36 years, 9 years

Hint :

Let the present age of the man be x years. Then, present age of his son is (45 – x) years. Five years ago, man’s age = (x – 5) years. Son’s age = (45 – x – 5) years.

∴ (x – 5) (45 – x – 5) = 4(x – 5)

Solution :Let the present age of a man be

ryears & let the present age of son bemyears respectively;The age of man’s was = (r – 5) years .

The age of son’s was = (m – 5) years .

Now;

As we know that never may 5 years the age of man, so not acceptable .∴ Putting the value of r =36in equation (1),we get;Thus;

The present age of man’s = r = 36 years .The present age of son’s = m = 9 years .