## The sum of the digits of a 2-digit number 19 if the difference between the number and the number formed by reversing the positions

Question

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## Answers ( )

Answer:Let the two digit number is pq on reversing the number we get qp therefore pq – qp =27. In first number pq, p is at the place of tens and q is at unity. Therefore it’s value is =(10p + q) In second case value is reversed

so qp =( 10q + p) Hence difference between two digits

(10p +q) – (10q – p) = 27

9p – 9q = 27 or p – q = 3

Difference between two digits is 3

Also digit is 96. It’s reverse is 69,so their difference is 96–69=27, and 9–6=3