The sum of the digits of a 2-digit number 19 if the difference between the number and the number formed by reversing the positions

Question

The sum of the digits of a 2-digit number 19
if the difference between the number and the
number formed by reversing the positions of its digits is 27, find the number​

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Luna 1 month 2021-08-21T23:10:24+00:00 1 Answer 0 views 0

Answers ( )

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    2021-08-21T23:12:01+00:00

    Answer:

    Let the two digit number is pq on reversing the number we get qp therefore pq – qp =27. In first number pq, p is at the place of tens and q is at unity. Therefore it’s value is =(10p + q) In second case value is reversed

    so qp =( 10q + p) Hence difference between two digits

    (10p +q) – (10q – p) = 27

    9p – 9q = 27 or p – q = 3

    Difference between two digits is 3

    Also digit is 96. It’s reverse is 69,so their difference is 96–69=27, and 9–6=3

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