The sum of three consecutive multiples of 11 is 636. Find these multiples. ​

Question

The sum of three consecutive multiples of 11 is 636. Find these multiples. ​

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Amelia 1 week 2021-10-14T11:27:28+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-14T11:28:40+00:00

    Three consecutive multiples are 201 , 212 and 223

    Given:

    The sum of 3 consecutive multiples of 11 is 636.

    To Find:

    Solution:

    Consider the:

    • One multiple as – x
    • 2nd multiple = x + 11
    • 3rd multiple = x + 22

    So,

    → x + (x + 11) + (x + 22) = 636 x + (x + 11) +(x + 22) = 636

    → x + x + 11 + x + 22 = 636x + x+11 + x + 22 = 636

    → 3x + 33 = 6363x + 33 = 636

    → 3x = 636 – 33 = 6033x = 636 – 33 = 603

    → x = \sf \dfrac{603}{3} = 201

    0
    2021-10-14T11:29:23+00:00

    Let one multiple be x

    2nd multiple = x + 11

    And 3rd multiple = x + 22

    A.T.Q

    x + (x  + 11) + (x + 22) = 636

    x + x + 11 + x + 22 = 636

    3x + 33 = 636

    3x = 636 - 33 = 603

    x =  \frac{603}{3}  = 201

    Thus multiples are 201 , 212 and 223

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