the two zeroes of a quadratic polynomial are – 4 and -6 . find the sum of product of the zeroes . what is the value of cofficent b ? ​

Question

the two zeroes of a quadratic polynomial are – 4 and -6 . find the sum of product of the zeroes . what is the value of cofficent b ?

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Isabelle 1 month 2021-08-13T01:53:50+00:00 1 Answer 0 views 0

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    2021-08-13T01:55:46+00:00

    Answer:

    • Sum of the zeros = -10
    • Product of zeros = 24
    • The value of coefficient b = 10

    Step-by-step explanation:

    Here

    α = -4

    β = -6

    Sum of the zeros = ( α + β )

    = -4 + -6 = -10

    Product of zeros = ( αβ )

    = -4 * -6 = 24

    To find the polynomial = k [ x^{2} – ( α + β )x + ( αβ ) ]

    ⇒ k [ x^{2} – ( -10 ) + 24 ]

    ⇒ k [ x^{2} + 10 + 24 ]

    Now if k = 1

    ⇒ 1 [ x^{2} + 10 + 24 ]

    x^{2} + 10 + 24 is the required polynomial.

    ∴ The value of coefficient b = 10

    hope it helps ..

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