## the two zeros of a quadratic polynomial are -4 and -6 find the sum and product of the zeros what is the value of coefficien b

Question

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## Answers ( )

Answer:

Sum of zeroes = -(coefficient of x)/ coefficient of x ^2

-4+(-6) = -b/a

-4-6 = -b/a

-10 = -b/a

10 = b/a

Product of zeroes = constant term / coefficient of x ^2

-4*-6 = c/a

24 = c/a

So , the value of b = 10

Hope it help you ✌️❣️

Answer:

b=20

Step-by-step explanation:

As -b/2a = som of root

-b/2a= -4+(-6) =-4-6=-10

-b/2a =-10 ………it depends value of a but a standard quadratic equation has a=1 so -b/2×1 =-10

-b =-20

b=20

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