The value of ‘K’ for which the quadratic equation 2kx2 + x + 3 = 0 has equal roots, is (a) 24 (b) 1/24 (c) -24 (d) – 1/24​

Question

The value of ‘K’ for which the quadratic equation 2kx2 + x + 3 = 0 has equal roots, is
(a) 24 (b) 1/24
(c) -24
(d) – 1/24​

in progress 0
Eva 3 weeks 2021-08-20T16:14:18+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-20T16:15:22+00:00

    Answer:

    Step-by-step explanation:

    Equal roots means that  D = 0,

    In the equation, a= 2k, b= 1 and c=3 and also D = 0 (given)

    D = b^2 – 4ac

    0 = (1)^2 – 4 (2k) (3)

    0 = 1 – 24k

    24k = 1

    k = 1/24     Hence correct option is (b) i.e. 1/24.

    Follow me for more such answers. Thank you.

    0
    2021-08-20T16:15:49+00:00

    2kx^2+x+3
    It has equal roots..,so discriminant D=0
    D=b^2-4ac
    (In the given equation.., a=2 , b=1 , c=3)
    (1)^2-4(1)(3)=0
    1-24k=0
    -24k=-1
    K=-1/-24
    Therefore k=1/24
    Option (b) is correct
    Hope this helps you.. 🙂

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )