The values of A and B,if √3+√2/√3-√6=a+b√6​

Question

The values of A and B,if
√3+√2/√3-√6=a+b√6​

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Parker 7 months 2021-10-13T16:56:36+00:00 2 Answers 0 views 0

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    0
    2021-10-13T16:57:50+00:00

    answer — √3+√2 /√3-√6===[√3+√2] √3+√6 /-3

    ⇒3+√18+√6 +√12 =a +b√6

    ⇒√6[√3 + √2] +3 =a +b√6

    a = 3  b= √2+√3

    pls mark this answer as the brainiest answer

    0
    2021-10-13T16:58:05+00:00

    Answer:

    Secondary School Math 5 points

    If √3+√2/√3-√2=a+b√6,then find the value of a and b

    Ask for details Follow Report by Pritipal 22.05.2018

    Answers

    Me · Beginner

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    AJIT1258

    AJIT1258 Expert

    Soln: Here, just we have to substitute the values of ‘a’ & ‘b’. That’s it! Come, let us solve.

    = a²+b²

    = [(√3+√2)/(√3-√2)]² + [(√3-√2)/(√3+√2)]²

    = (√3+√2)²/(√3-√2)² + (√3-√2)²/(√3+√2)² [b/z, (a/b)² = a²/b²]

    = [(√3)²+2(√3)(√2)+(√2)²]/[(√3)²-2(√3)(√2)+(√2)²] + [(√3)²-2(√3)(√2)+(√2)²]/[(√3)²+2(√3)(√2)+(√2)²] [b/z, (a+b)²=(a²+2ab+b²) & (a-b)²=(a²-2ab+b²)]

    = (3+2√6+2)/(3–2√6+2)+(3–2√6+2)/(3+2√6+2)

    = (5+2√6)/(5–2√6)+(5–2√6)/(5+2√6)

    Now, take LCM,

    = [(5+2√6)(5+2√6)+(5–2√6)(5–2√6)]/(5–2√6)(5+2√6)

    = [(5+2√6)²+(5–2√6)²]/(5)²-(2√6)²

    = {[(5)²+2(5)(2√6)+(2√6)²]+[(5)²-2(5)(2√6)+(2√6)²]}/25–4(√6)(√6)

    = [(25+20√6+24)+(25–20√6+24)]/25–24

    = (49+20√6+49–20√6)/ 1

    = 98/1

    = 98

    Hence, a²+b²=98

    Therefore, 98 is the answer for your question. Thank you.

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