The vertical angle of an isosceles triangle is 30° more than its base angle. Find all the angles of the triangle​

Question

The vertical angle of an isosceles triangle is 30° more than its base angle. Find all the angles of
the triangle​

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Autumn 2 weeks 2021-09-09T06:10:24+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-09T06:12:00+00:00

    Answer:

    50

    Step-by-step explanation:

    let the traingle be ABC where angle A is 30°more than base angle

    let the base angle be x

    both angle B and C are equal as angle opposite to equal side are equal

    so A=30°+x

    B=x

    C=x

    A+B+C=180°(angle sum property)

    x+30+x+x=180°

    3x=180-30

    3x=150

    x=50

    pls mark me as brainliest

    0
    2021-09-09T06:12:18+00:00

    Step-by-step explanation:

    Base angles = x

    Vertical angle = x + 30°

    x + x + x + 30° = 180° (Angle Sum property)

    3x + 30° = 180°

    3x = 180° – 30°

    3x = 150°

    x = 150°/3

    x = 50°

    Both base angles = 50°

    Vertical angle = x + 30°

    = 50° + 30°

    = 80°  

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