The width of a rectangle is two- thirds its length. If the perimeter is 180 metres, find the length. * 45 54 50

Question

The width of a rectangle is two-
thirds its length. If the perimeter is
180 metres, find the length. *
45
54
50
56
The rectangle’s breadth will be *
30
35
33
36
*
in the above rectangle , if the breadth is increased by 18 which figure will be formed
*square
triangle
pentagon

if 4/5 parts of length is taken and 7/8 parts of the breadth is taken the new perimeter will be*

146.8

148.6

147.9

149.4

Find The area of new rectangle*

1345.9

1360.8

1367.3

1354.5​

in progress 0
Isabelle 2 weeks 2021-09-07T13:37:02+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-07T13:38:02+00:00

    Step-by-step explanation:

    b=2l/3

    perimeter=2(l+b)

    180=2(l+b)

    by substituting b in terms of l and solve it to get

    l=54

    b=36

    and if we increase the width by 18 then it will become a square.

    and 4/5 parts of length is 43.2

    7/8 parts of width is 31.5

    new perimeter is 149.4

    new area is 1360.8.

    0
    2021-09-07T13:38:53+00:00

    Step-by-step explanation:

    let length =x

    breadth = 2x/3

    perimeter = 2(x+2x/3) =180

    2(3x+2x/3)=180

    6x+4x/3=180

    10x=540

    x=54= length

    breadth =2/3×x=36

    breadth+18= 54

    then l=b

    the figure is a square

    then 4/5l +7/8b=

    216/5=l and 7/8 × 36

    43.2 = l and 31.5 = b

    p= 2(l+b)

    =2(43.2+31.5)=

    149.4

    area = 43.2× 31.5

    1360.8

    hope u understand

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