## There are two friends A and B. A starts with his car at the speed 40 kmph. B starts one hour later from the same place, in the same directio

Question

There are two friends A and B. A starts with his car at the speed 40 kmph. B starts one hour later from the same place, in the same direction on his bike at the speed of 50 kmph. After how many hours will they meet

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6 days 2021-09-10T20:56:26+00:00 2 Answers 0 views 0

1. ### FORMULATO BEIMPLEMENTED

For a moving body traveling a distance

### GIVEN

There are two friends A and B. A starts with his car at the speed 40 kmph. B starts one hour later from the same place, in the same direction on his bike at the speed of 50 kmph

### TODETERMINE

The time after which they will meet

### CALCULATION

Let at a distance of x km from starting point they will meet

The speed of A & B is 40 kmph & 50 kmph respectively

So the time required for A to travel the distance of x km is

So the time required for B to travel the distance of x km is

By the given condition

So the time required for A to travel the distance of 200 km is

So the time required for B to travel the distance of 200 km is

Hence after 5 hours from starting of A & after 4 hours of starting of B the two friends A & B will meet

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X is the greatest no by which when 2460,2633,2806 are divided in each case same remainder is obtained.What is the sum of all digits of X

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2. Given :  There are two friends A and B. A starts with his car at the speed 40 kmph. B starts one hour later from the same place, in the same direction on his bike at the speed of 50 kmph.

To Find : After how many hours will they meet

Solution:

Let say they meet after T hours from when A starts

Speed of A = 40 km/hr

Time = T hrs

Distance = Speed x Time

=> Distance = 40T  km

Speed of B = 50 km/hr

B starts after 1 hr

Time = T-1  hrs

=> Distance = 50(T-1)  km

40T = 50(T-1)

=> 4T = 5(T – 1)

=> 4T = 5T – 5

=> T = 5

After 5 hrs from when A starts and after 4 hrs from when B starts