There were two candidates in an election. 8% of voters did not cast their votes. The winning candidate secured 48% vot

Question

There were two candidates in an election. 8% of

voters did not cast their votes. The winning

candidate secured 48% vote of total votes and won

by 1100 votes. Find the total votes.​

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Ivy 1 week 2021-09-10T12:08:29+00:00 1 Answer 0 views 0

Answers ( )

  1. Emma
    0
    2021-09-10T12:10:10+00:00

    HERE’S THE ANSWER MATE

    Step-by-step explanation:

    Let total number of votes be x

    Now, 1st candidate won 48% of total votes =

    48x/100

    But, 8% from total voters don’t give vote ; so votes gives actually = x – 8x/100

    = 92x/100

    Hmn, now 2nd candidate must have got

    92x/100 – 48x/100 = 44x/100, then

    Now, 2nd candidate lost by 1st candidate by

    1100 votes :-

    48x/100 = 44x/100 + 1100

    48x/100 – 44x/100 = 1100

    4x/100 = 1100

    x= 100/4 × 1100

    x = 27,500 votes are polled

    Hope it helps☺!

    HOPE THIS WILL HELP YOU… PLEASE MARK AS BRAINLIST…ALSO FOLLOW ME..

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