let one number be x Other number will be x-5 193=(x)2 +(x-5)2 193=x2+x2+25-10x 193-25=2×2-10x 168=2×2-10x 2×2-10x-168=0 Dividing by 2 on both sides x2-5x-84=0 x2-5x+(5/2)^2-(5/2)^2-84=0 (x+5/2)^2=(5/2)^2+84 (x+5/2)^2=25/4+336/4 (x+5/2)^2=25+336/4 (x+5/2)^2=361/4 x+5/2=+-rt361/2 Then solve it equating both possibilities that is rt 361 as + or – then u will get alpha and beta. Plz mark it as brainliest I have worked hard so much to type.

## Answers ( )

let one number be x

Other number will be x-5

193=(x)2 +(x-5)2

193=x2+x2+25-10x

193-25=2×2-10x

168=2×2-10x

2×2-10x-168=0

Dividing by 2 on both sides

x2-5x-84=0

x2-5x+(5/2)^2-(5/2)^2-84=0

(x+5/2)^2=(5/2)^2+84

(x+5/2)^2=25/4+336/4

(x+5/2)^2=25+336/4

(x+5/2)^2=361/4

x+5/2=+-rt361/2

Then solve it equating both possibilities that is rt 361 as + or – then u will get alpha and beta. Plz mark it as brainliest I have worked hard so much to type.

Plzzzzzzz……………