two year ago my age was 4.5 times of my son six years ago my age was twise the spuare of the age of my son . what is the present age of my s

Question

two year ago my age was 4.5 times of my son six years ago my age was twise the spuare of the age of my son . what is the present age of my son​

in progress 0
Ayla 4 weeks 2021-08-17T21:53:02+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-17T21:54:55+00:00

    Answer:

    It is given that my age was twice the square of the age of my son. y = 4.25 is discarded as age cannot be fractional. So, present age of son is y = 10 years.

    Step-by-step explanation:

    Let 2 years ago, son’s age be x.

    So my age(2 years ago) =4.5 x

    So, 6 years ago,

    My age=4.5x-4

    Son’s age=x-4

    B/C,

    4.5x-4=2((x-4)^2)

    or, 4x^2–41x+72=0

    Solving the quadratic, we get-

    x=8 or x=2.5(not possible)

    So my present age of=4.5x+2=38

    My son’s present age=x+2=10.(Ans)

    it will very help you

    please mark me brainest

    thanks and please rate    ………..

    thanks for giving chance to answer

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )