Two years ago, a man was six times as old as his son. In 18 years, he will be twice as old as his son. The age of the man (in yea

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Two years ago, a man was six times as old as his son. In 18 years, he
will be twice as old as his son. The age of the man (in years) is​

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Bella 1 month 2021-08-18T12:46:40+00:00 1 Answer 0 views 0

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    2021-08-18T12:47:43+00:00

    Step-by-step explanation:

    Let the present ages of father and son be x and y, respectively.

    As per the problem, six years ago,

    (x−6)=3(y−6)

    Six years later, (x+6)=2(y+6)

    Solving these two equations, we get father’s age is 42 years, and son’s age is 18 years.

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