Two years ago, a man was six times as old as his son. In 18 years, he will be twice as old as his son. The age of the man (in yea Question Two years ago, a man was six times as old as his son. In 18 years, hewill be twice as old as his son. The age of the man (in years) is in progress 0 Math Bella 1 month 2021-08-18T12:46:40+00:00 2021-08-18T12:46:40+00:00 1 Answer 0 views 0

## Answers ( )

Step-by-step explanation:Let the present ages of father and son be x and y, respectively.

As per the problem, six years ago,

(x−6)=3(y−6)

Six years later, (x+6)=2(y+6)

Solving these two equations, we get father’s age is 42 years, and son’s age is 18 years.