Use remainder theorem to find the value of k.It being given that x³+2x²+kx+3 is divisible by x-3.Then the remainder is 21.[Don’t spam]

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Use remainder theorem to find the value of k.It being given that x³+2x²+kx+3 is divisible by x-3.Then the remainder is 21.[Don’t spam]

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Quinn 4 weeks 2021-09-22T23:06:55+00:00 2 Answers 0 views 0

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    0
    2021-09-22T23:07:57+00:00

    Answer:

    using remainder theorem

    x = 3

    x^3 + 2x^2 + kx + 3 = 21

    ( 3 )^3 + 2 ( 3 )^2 + k ( 3 ) + 3 = 21

    27 + 18 + 3k + 3 = 21

    3k = 21 – 48

    3k = – 27

    k = – 27 / 3

    k = – 9

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    0
    2021-09-22T23:08:43+00:00

    Answer:

    -9

    Step-by-step explanation:

    p(x) = x³ + 2x² + kx + 3

    g(x) = x – 3

    x – 3 = 0

    x = 3

    Substitute this in p(x)

    x³ + 2x² + kx + 3

    (3)³ + 2(3)² + k(3) + 3 = 21

    27 + 18 + 3k + 3 = 21

    3k = 21 – 48

    k = -27 /3

    k = -9

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