Use the discriminant to determine the number of real roots the equation has. 3×2 – 5x + 1 =0 (a) One real root (a double root),

Question

Use the discriminant to determine the number of real roots the equation has. 3×2 – 5x + 1 =0

(a) One real root (a double root),
(b) Two distinct real roots,
(c) Three real roots,
(d) None (two imaginary roots)

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Brielle 1 month 2021-10-26T12:41:03+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-26T12:42:13+00:00

    Answer:

    Discriminant = bx2 – 4ac

    Compare the above equation 3×2 – 5x + 1 =0 with ax2 + bx + c = 0

    We get, a = 3, b = -5, c = 1

    Put the value of a, b and c;

    Discriminant = bx2 – 4ac

    Discriminant = (-5)2 – 4 × 3 × 1

    = 25 – 12

    = 13 [13 > 0]

    Therefore, discriminant is positive.

    So the given equation has two distinct real roots.

    Answer – B

    ⤴️_____HOPE HELP YOU_____⤴️

    0
    2021-10-26T12:42:32+00:00

    Answer:

    Discriminant = bx2 – 4ac

    Compare the above equation 3×2 – 5x + 1 =0 with ax2 + bx + c = 0

    We get, a = 3, b = -5, c = 1

    Put the value of a, b and c;

    Discriminant = bx2 – 4ac

    Discriminant = (-5)2 – 4 × 3 × 1

    = 25 – 12

    = 13 [13 > 0]

    Therefore, discriminant is positive.

    So the given equation has two distinct real roots.

    Answer – B

    ⤴️_____HOPE HELP YOU_____⤴️

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