## Water flows through a cylindrical pipe, whose inner radius is 1 cm, at the rate of 70 cm/s in an empty tank. How much water will flow in the

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## Answers ( )

Answer:Step-by-step explanation:Internal radius of the pipe , r = 1 cm .

→ Length of water flowing in 1 sec , h = 80 cm .

▶ Then, Volume of water flowing in 1 second

= πr²h .

= ( π × 1 × 1 × 80 ) cm³ .

= 80π cm³ .

▶ Volume of water flowing in 30 minutes [ Half an hour ]

= ( 80π × 60 × 30 ) cm³ .

= 144,000π cm³ .

→ Radius of cylindrical tank, R = 40 cm .

Let the rise in level of water be H cm .

▶ Volume of water in the tank

= πR²H .

= ( π × 40 × 40 × H ) cm³ .

= 1600πH cm³ .

▶ Volume of water in the tank = Volume of water flown through a pipe .

✔✔ Hence, rise in level = 90 cm ✅✅ .

THANKS

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