Water flows through a cylindrical pipe, whose inner radius is 1 cm, at the rate of 70 cm/s in an empty tank. How much water will flow in the

Question

Water flows through a cylindrical pipe, whose inner radius is 1 cm, at the rate of 70 cm/s in an empty tank. How much water will flow in the tank in half an hour?
(
use pie as 22/7

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Aaliyah 4 days 2021-09-14T19:26:13+00:00 2 Answers 0 views 0

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    0
    2021-09-14T19:27:14+00:00

    Answer:

    Step-by-step explanation:

    \pi = 22/7  , r = 1 cm  , h =  70 cm \\ v = \pi r2h\\v = 22/7 *1*2*70\\v = 440

    0
    2021-09-14T19:27:46+00:00

    Internal radius of the pipe , r = 1 cm .

    → Length of water flowing in 1 sec , h = 80 cm .

    ▶ Then, Volume of water flowing in 1 second

    = πr²h .

    = ( π × 1 × 1 × 80 ) cm³ .

    = 80π cm³ .

    ▶ Volume of water flowing in 30 minutes [ Half an hour ]

    = ( 80π × 60 × 30 ) cm³ .

    = 144,000π cm³ .

    → Radius of cylindrical tank, R = 40 cm .

    Let the rise in level of water be H cm .

    ▶ Volume of water in the tank

    = πR²H .

    = ( π × 40 × 40 × H ) cm³ .

    = 1600πH cm³ .

    ▶ Volume of water in the tank = Volume of water flown through a pipe .

    ✔✔ Hence, rise in level = 90 cm ✅✅ .

    THANKS

    Read more on Brainly.in – https://brainly.in/question/7339507#readmore

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