So, for the values of x, for which y is 0, are the zeroes of the polynomial f(x). Now, when f(x) is traced in x-y plane, there will points intersecting both x and y axis/ either axis/ none of the axis.

Where the graph intersects x-axis, the coordinate would be, y=0, x=x1( x1 being any number). This means at this point the polynomial , f(x) will have the values (x1,0).

That is why, when we put x=x1 in f(x) , the value turns out to be 0, i.e. x1 is a zero of the polynomial f(x).

## Answers ( )

Answer:Step-by-step explanation:Let y=f(x) be the polynomial.

So, for the values of x, for which y is 0, are the zeroes of the polynomial f(x). Now, when f(x) is traced in x-y plane, there will points intersecting both x and y axis/ either axis/ none of the axis.

Where the graph intersects x-axis, the coordinate would be, y=0, x=x1( x1 being any number). This means at this point the polynomial , f(x) will have the values (x1,0).

That is why, when we put x=x1 in f(x) , the value turns out to be 0, i.e. x1 is a zero of the polynomial f(x).

Hope this helps you!

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