write in descending order  2\sqrt[4]{6} 78 \sqrt[4]{2}

Question

write in
descending order
 2\sqrt[4]{6}
78 \sqrt[4]{2}

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Amelia 2 weeks 2021-09-07T04:48:32+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-09-07T04:50:01+00:00

    Step-by-step explanation:

    2\sqrt[4]{6}

    78 \sqrt[4]{2}

    In descending order:

     2 \sqrt[4]{6}  = 19.60

    78 \sqrt[4]{2}  =441.24

    hence,

    78 \sqrt[4]{2} > 2 \sqrt[4]{6}

    hope it helps 🙂

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