write the nuber of zeroes in the end of a number whose prime factorization is 2*2×5*3×3*2×17​

Question

write the nuber of zeroes in the end of a number whose prime factorization is 2*2×5*3×3*2×17​

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Aaliyah 3 weeks 2021-09-06T06:15:54+00:00 1 Answer 0 views 0

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    2021-09-06T06:17:41+00:00

    Answer:

    concept : if we multiply 10 with any number, we get a zero in unit digit of resultant number.similarly when we multiply 100 with any number, we get two zeros in the end of resultant number and so on. for example ; 10 × 45 = 450.

    100 × 45 = 4500.

    means, for getting number of zeros in the end of a number we have to check how much multiple of 10 are present in that number.

    here, given prime factorisation of number is 2² × 5³ × 3² × 17

    = 2² × 5² × 5 × 3² × 17

    = (2 × 5)² × 5 × 3² × 17

    = (10)² × 5 × 3² × 17

    = 10 × 10 × 5 × 3² × 17

    here , there are two 10 are present in the prime factorisation of number so, \textbf{two zeros}two zeros are present in the end of the given number.

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